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203553400047 = 367851133349
BaseRepresentation
bin1011110110010010111…
…0100110010011101111
3201110101222122002222120
42331210232212103233
511313334132300142
6233302223444023
720464146231624
oct2754456462357
9643358562876
10203553400047
1179365651258
1233549756613
131626c56465a
149bcddc034b
1554653cd7ec
hex2f64ba64ef

203553400047 has 4 divisors (see below), whose sum is σ = 271404533400. Its totient is φ = 135702266696.

The previous prime is 203553400033. The next prime is 203553400081. The reversal of 203553400047 is 740004355302.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-203553400047 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 203553399990 and 203553400017.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (203553400147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33925566672 + ... + 33925566677.

It is an arithmetic number, because the mean of its divisors is an integer number (67851133350).

Almost surely, 2203553400047 is an apocalyptic number.

203553400047 is a deficient number, since it is larger than the sum of its proper divisors (67851133353).

203553400047 is an equidigital number, since it uses as much as digits as its factorization.

203553400047 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67851133352.

The product of its (nonzero) digits is 50400, while the sum is 33.

Adding to 203553400047 its reverse (740004355302), we get a palindrome (943557755349).

The spelling of 203553400047 in words is "two hundred three billion, five hundred fifty-three million, four hundred thousand, forty-seven".

Divisors: 1 3 67851133349 203553400047