20401132013131 has 4 divisors (see below), whose sum is σ = 20401336818064. Its totient is φ = 20400927208200.

The previous prime is 20401132013029. The next prime is 20401132013179. The reversal of 20401132013131 is 13131023110402.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20401132013131 - 2¹⁵ = 20401131980363 is a prime.

It is a super-2 number, since 2×20401132013131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20401132013191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102252975 + ... + 102452296.

It is an arithmetic number, because the mean of its divisors is an integer number (5100334204516).

Almost surely, 2^{20401132013131} is an apocalyptic number.

20401132013131 is a deficient number, since it is larger than the sum of its proper divisors (204804933).

20401132013131 is an equidigital number, since it uses as much as digits as its factorization.

20401132013131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 204804932.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 20401132013131 its reverse (13131023110402), we get a palindrome (33532155123533).

The spelling of 20401132013131 in words is "twenty trillion, four hundred one billion, one hundred thirty-two million, thirteen thousand, one hundred thirty-one".