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204013344101 = 729144763443
BaseRepresentation
bin1011111000000000100…
…1001001010101100101
3201111121001002200121112
42332000021021111211
511320304404002401
6233420013554405
720511432545450
oct2760011112545
9644531080545
10204013344101
117958123a006
12336577a5a05
13163139335b8
149c3510a497
1554909833bb
hex2f80249565

204013344101 has 4 divisors (see below), whose sum is σ = 233158107552. Its totient is φ = 174868580652.

The previous prime is 204013344083. The next prime is 204013344107. The reversal of 204013344101 is 101443310402.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 204013344101 - 218 = 204013081957 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (204013344107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14572381715 + ... + 14572381728.

It is an arithmetic number, because the mean of its divisors is an integer number (58289526888).

Almost surely, 2204013344101 is an apocalyptic number.

It is an amenable number.

204013344101 is a deficient number, since it is larger than the sum of its proper divisors (29144763451).

204013344101 is an equidigital number, since it uses as much as digits as its factorization.

204013344101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29144763450.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 204013344101 its reverse (101443310402), we get a palindrome (305456654503).

The spelling of 204013344101 in words is "two hundred four billion, thirteen million, three hundred forty-four thousand, one hundred one".

Divisors: 1 7 29144763443 204013344101