204020000211113 has 2 divisors, whose sum is σ = 204020000211114. Its totient is φ = 204020000211112.

The previous prime is 204020000211073. The next prime is 204020000211169. The reversal of 204020000211113 is 311112000020402.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 160769542737049 + 43250457474064 = 12679493^2 + 6576508^2 .

It is a cyclic number.

It is not a de Polignac number, because 204020000211113 - 2⁸ = 204020000210857 is a prime.

It is a super-3 number, since 3×204020000211113³ (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 204020000211091 and 204020000211100.

It is not a weakly prime, because it can be changed into another prime (204020000211613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 102010000105556 + 102010000105557.

It is an arithmetic number, because the mean of its divisors is an integer number (102010000105557).

Almost surely, 2^{204020000211113} is an apocalyptic number.

It is an amenable number.

204020000211113 is a deficient number, since it is larger than the sum of its proper divisors (1).

204020000211113 is an equidigital number, since it uses as much as digits as its factorization.

204020000211113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 204020000211113 its reverse (311112000020402), we get a palindrome (515132000231515).

The spelling of 204020000211113 in words is "two hundred four trillion, twenty billion, two hundred eleven thousand, one hundred thirteen".