Base | Representation |
---|---|
bin | 101110011001001011001001… |
… | …110111110000101001100111 |
3 | 222202110001011121120110200111 |
4 | 232121023021313300221213 |
5 | 203220443112404421013 |
6 | 2001542421314153451 |
7 | 60656260653026251 |
oct | 5631131167605147 |
9 | 882401147513614 |
10 | 204040103201383 |
11 | 5a016a15a40759 |
12 | 1aa74409882887 |
13 | 89b0b8c631877 |
14 | 3855845116cd1 |
15 | 188c840b1973d |
hex | b992c9df0a67 |
204040103201383 has 2 divisors, whose sum is σ = 204040103201384. Its totient is φ = 204040103201382.
The previous prime is 204040103201371. The next prime is 204040103201513. The reversal of 204040103201383 is 383102301040402.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 204040103201383 - 237 = 203902664247911 is a prime.
It is a super-2 number, since 2×2040401032013832 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (204040106201383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 102020051600691 + 102020051600692.
It is an arithmetic number, because the mean of its divisors is an integer number (102020051600692).
Almost surely, 2204040103201383 is an apocalyptic number.
204040103201383 is a deficient number, since it is larger than the sum of its proper divisors (1).
204040103201383 is an equidigital number, since it uses as much as digits as its factorization.
204040103201383 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 204040103201383 its reverse (383102301040402), we get a palindrome (587142404241785).
The spelling of 204040103201383 in words is "two hundred four trillion, forty billion, one hundred three million, two hundred one thousand, three hundred eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •