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20412140326117 is a prime number
BaseRepresentation
bin1001010010000100100100…
…10111111000110011100101
32200021101022011012100020121
410221002102113320303211
510133413030410413432
6111225112515401541
74204504603005451
oct451022227706345
980241264170217
1020412140326117
11655a816086101
1223580145b32b1
13b50b19b794a7
14507d4a929661
15255e774bd197
hex1290925f8ce5

20412140326117 has 2 divisors, whose sum is σ = 20412140326118. Its totient is φ = 20412140326116.

The previous prime is 20412140326111. The next prime is 20412140326139. The reversal of 20412140326117 is 71162304121402.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12624100347681 + 7788039978436 = 3553041^2 + 2790706^2 .

It is a cyclic number.

It is not a de Polignac number, because 20412140326117 - 219 = 20412139801829 is a prime.

It is a super-2 number, since 2×204121403261172 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20412140326111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10206070163058 + 10206070163059.

It is an arithmetic number, because the mean of its divisors is an integer number (10206070163059).

Almost surely, 220412140326117 is an apocalyptic number.

It is an amenable number.

20412140326117 is a deficient number, since it is larger than the sum of its proper divisors (1).

20412140326117 is an equidigital number, since it uses as much as digits as its factorization.

20412140326117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 34.

Adding to 20412140326117 its reverse (71162304121402), we get a palindrome (91574444447519).

The spelling of 20412140326117 in words is "twenty trillion, four hundred twelve billion, one hundred forty million, three hundred twenty-six thousand, one hundred seventeen".