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2041214111 is a prime number
BaseRepresentation
bin111100110101010…
…0111010010011111
312021020220102100122
41321222213102133
513140022322421
6534314145155
7101404014356
oct17152472237
95236812318
102041214111
11958237412
1248b7221bb
13266b77701
1415514699d
15be3042ab
hex79aa749f

2041214111 has 2 divisors, whose sum is σ = 2041214112. Its totient is φ = 2041214110.

The previous prime is 2041214107. The next prime is 2041214117. The reversal of 2041214111 is 1114121402.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2041214111 - 22 = 2041214107 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2041214111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2041214117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1020607055 + 1020607056.

It is an arithmetic number, because the mean of its divisors is an integer number (1020607056).

Almost surely, 22041214111 is an apocalyptic number.

2041214111 is a deficient number, since it is larger than the sum of its proper divisors (1).

2041214111 is an equidigital number, since it uses as much as digits as its factorization.

2041214111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64, while the sum is 17.

The square root of 2041214111 is about 45179.7975980415. The cubic root of 2041214111 is about 1268.5166948817.

Adding to 2041214111 its reverse (1114121402), we get a palindrome (3155335513).

The spelling of 2041214111 in words is "two billion, forty-one million, two hundred fourteen thousand, one hundred eleven".