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204143210471 is a prime number
BaseRepresentation
bin1011111000011111100…
…0100010111111100111
3201111221002110120210002
42332013320202333213
511321041130213341
6233440533251515
720514600441554
oct2760770427747
9644832416702
10204143210471
117963857a592
1233693193b9b
13163348032c5
149c48473a2b
15549c08729b
hex2f87e22fe7

204143210471 has 2 divisors, whose sum is σ = 204143210472. Its totient is φ = 204143210470.

The previous prime is 204143210389. The next prime is 204143210473. The reversal of 204143210471 is 174012341402.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-204143210471 is a prime.

It is a super-3 number, since 3×2041432104713 (a number of 35 digits) contains 333 as substring.

Together with 204143210473, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (204143210473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 102071605235 + 102071605236.

It is an arithmetic number, because the mean of its divisors is an integer number (102071605236).

Almost surely, 2204143210471 is an apocalyptic number.

204143210471 is a deficient number, since it is larger than the sum of its proper divisors (1).

204143210471 is an equidigital number, since it uses as much as digits as its factorization.

204143210471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5376, while the sum is 29.

Adding to 204143210471 its reverse (174012341402), we get a palindrome (378155551873).

The spelling of 204143210471 in words is "two hundred four billion, one hundred forty-three million, two hundred ten thousand, four hundred seventy-one".