Base | Representation |
---|---|
bin | 11101110000000000100… |
… | …101110000110100000111 |
3 | 21020102222202020200210112 |
4 | 131300000211300310013 |
5 | 231443430032112132 |
6 | 4203105130143235 |
7 | 300463331045654 |
oct | 35600045606407 |
9 | 7212882220715 |
10 | 2044414332167 |
11 | 719038657a29 |
12 | 29027a281b1b |
13 | 11aa310272ac |
14 | 70d43426c2b |
15 | 382a72ceab2 |
hex | 1dc00970d07 |
2044414332167 has 2 divisors, whose sum is σ = 2044414332168. Its totient is φ = 2044414332166.
The previous prime is 2044414332143. The next prime is 2044414332197. The reversal of 2044414332167 is 7612334144402.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2044414332167 - 222 = 2044410137863 is a prime.
It is a super-2 number, since 2×20444143321672 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2044414332197) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1022207166083 + 1022207166084.
It is an arithmetic number, because the mean of its divisors is an integer number (1022207166084).
Almost surely, 22044414332167 is an apocalyptic number.
2044414332167 is a deficient number, since it is larger than the sum of its proper divisors (1).
2044414332167 is an equidigital number, since it uses as much as digits as its factorization.
2044414332167 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 387072, while the sum is 41.
Adding to 2044414332167 its reverse (7612334144402), we get a palindrome (9656748476569).
The spelling of 2044414332167 in words is "two trillion, forty-four billion, four hundred fourteen million, three hundred thirty-two thousand, one hundred sixty-seven".
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