2045254401433 has 4 divisors (see below), whose sum is σ = 2050512125220. Its totient is φ = 2039996677648.

The previous prime is 2045254401431. The next prime is 2045254401439. The reversal of 2045254401433 is 3341044525402.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1062245606409 + 983008795024 = 1030653^2 + 991468^2 .

It is a cyclic number.

It is not a de Polignac number, because 2045254401433 - 2¹ = 2045254401431 is a prime.

It is a super-2 number, since 2×2045254401433² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2045254401392 and 2045254401401.

It is not an unprimeable number, because it can be changed into a prime (2045254401431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2628861310 + ... + 2628862087.

It is an arithmetic number, because the mean of its divisors is an integer number (512628031305).

Almost surely, 2^{2045254401433} is an apocalyptic number.

It is an amenable number.

2045254401433 is a deficient number, since it is larger than the sum of its proper divisors (5257723787).

2045254401433 is an equidigital number, since it uses as much as digits as its factorization.

2045254401433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5257723786.

The product of its (nonzero) digits is 230400, while the sum is 37.

Adding to 2045254401433 its reverse (3341044525402), we get a palindrome (5386298926835).

The spelling of 2045254401433 in words is "two trillion, forty-five billion, two hundred fifty-four million, four hundred one thousand, four hundred thirty-three".