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2050233433121 is a prime number
BaseRepresentation
bin11101110101011011011…
…011110111110000100001
321021000000021220122122002
4131311123123313300201
5232042334224324441
64205510401453345
7301060460432606
oct35653333676041
97230007818562
102050233433121
11720554361675
12291423041255
1311b44a795bb3
14713361c66ad
15384e80d2b9b
hex1dd5b6f7c21

2050233433121 has 2 divisors, whose sum is σ = 2050233433122. Its totient is φ = 2050233433120.

The previous prime is 2050233433109. The next prime is 2050233433147. The reversal of 2050233433121 is 1213343320502.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1994622360721 + 55611072400 = 1412311^2 + 235820^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2050233433121 is a prime.

It is not a weakly prime, because it can be changed into another prime (2050233433151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1025116716560 + 1025116716561.

It is an arithmetic number, because the mean of its divisors is an integer number (1025116716561).

Almost surely, 22050233433121 is an apocalyptic number.

It is an amenable number.

2050233433121 is a deficient number, since it is larger than the sum of its proper divisors (1).

2050233433121 is an equidigital number, since it uses as much as digits as its factorization.

2050233433121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960, while the sum is 29.

Adding to 2050233433121 its reverse (1213343320502), we get a palindrome (3263576753623).

The spelling of 2050233433121 in words is "two trillion, fifty billion, two hundred thirty-three million, four hundred thirty-three thousand, one hundred twenty-one".