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1213343320502 = 2606671660251
BaseRepresentation
bin10001101010000000111…
…001011100100110110110
311021222211222112000122002
4101222000321130212312
5124334411342224002
62325222514135302
7153442531025045
oct21520071344666
94258758460562
101213343320502
114286377442a5
121771a2281532
138a557b44521
1442a2470255c
1521866357002
hex11a80e5c9b6

1213343320502 has 4 divisors (see below), whose sum is σ = 1820014980756. Its totient is φ = 606671660250.

The previous prime is 1213343320487. The next prime is 1213343320523. The reversal of 1213343320502 is 2050233433121.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×12133433205023 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 303335830124 + ... + 303335830127.

It is an arithmetic number, because the mean of its divisors is an integer number (455003745189).

Almost surely, 21213343320502 is an apocalyptic number.

1213343320502 is a deficient number, since it is larger than the sum of its proper divisors (606671660254).

1213343320502 is an equidigital number, since it uses as much as digits as its factorization.

1213343320502 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 606671660253.

The product of its (nonzero) digits is 12960, while the sum is 29.

Adding to 1213343320502 its reverse (2050233433121), we get a palindrome (3263576753623).

The spelling of 1213343320502 in words is "one trillion, two hundred thirteen billion, three hundred forty-three million, three hundred twenty thousand, five hundred two".

Divisors: 1 2 606671660251 1213343320502