Base | Representation |
---|---|
bin | 111110100101011… |
… | …1010000110101001 |
3 | 12102100112122010020 |
4 | 1331022322012221 |
5 | 13300100331213 |
6 | 544214311053 |
7 | 103016542212 |
oct | 17512720651 |
9 | 5370478106 |
10 | 2100011433 |
11 | 988446743 |
12 | 4a7358489 |
13 | 2760c3120 |
14 | 15cc90409 |
15 | c456a923 |
hex | 7d2ba1a9 |
2100011433 has 16 divisors (see below), whose sum is σ = 3034616256. Its totient is φ = 1284079680.
The previous prime is 2100011429. The next prime is 2100011447. The reversal of 2100011433 is 3341100012.
It is not a de Polignac number, because 2100011433 - 22 = 2100011429 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (2100011533) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 165363 + ... + 177608.
It is an arithmetic number, because the mean of its divisors is an integer number (189663516).
Almost surely, 22100011433 is an apocalyptic number.
It is an amenable number.
2100011433 is a deficient number, since it is larger than the sum of its proper divisors (934604823).
2100011433 is a wasteful number, since it uses less digits than its factorization.
2100011433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 343144.
The product of its (nonzero) digits is 72, while the sum is 15.
The square root of 2100011433 is about 45825.8816936456. The cubic root of 2100011433 is about 1280.5814889296.
Adding to 2100011433 its reverse (3341100012), we get a palindrome (5441111445).
The spelling of 2100011433 in words is "two billion, one hundred million, eleven thousand, four hundred thirty-three".
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