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210011223113 is a prime number
BaseRepresentation
bin1100001110010110100…
…1001111010001001001
3202002002001011111211122
43003211221033101021
511420100333114423
6240251113205025
721113162641256
oct3034551172111
9662061144748
10210011223113
118107995130a
1234850400775
1316a5b438b33
14a24392642d
1556e22ec8c8
hex30e5a4f449

210011223113 has 2 divisors, whose sum is σ = 210011223114. Its totient is φ = 210011223112.

The previous prime is 210011223091. The next prime is 210011223167. The reversal of 210011223113 is 311322110012.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 161537274889 + 48473948224 = 401917^2 + 220168^2 .

It is a cyclic number.

It is not a de Polignac number, because 210011223113 - 26 = 210011223049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 210011223091 and 210011223100.

It is not a weakly prime, because it can be changed into another prime (210011223013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105005611556 + 105005611557.

It is an arithmetic number, because the mean of its divisors is an integer number (105005611557).

Almost surely, 2210011223113 is an apocalyptic number.

It is an amenable number.

210011223113 is a deficient number, since it is larger than the sum of its proper divisors (1).

210011223113 is an equidigital number, since it uses as much as digits as its factorization.

210011223113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 210011223113 its reverse (311322110012), we get a palindrome (521333333125).

The spelling of 210011223113 in words is "two hundred ten billion, eleven million, two hundred twenty-three thousand, one hundred thirteen".