Base | Representation |
---|---|
bin | 11110100011111000111… |
… | …010000001011000110010 |
3 | 21102202202222021211100002 |
4 | 132203320322001120302 |
5 | 233402021210000200 |
6 | 4244440512030002 |
7 | 304504634314652 |
oct | 36437072013062 |
9 | 7382688254302 |
10 | 2100120000050 |
11 | 73a723a98786 |
12 | 29b025b32302 |
13 | 12306ab9aa57 |
14 | 7390982a362 |
15 | 39967a1cbd5 |
hex | 1e8f8e81632 |
2100120000050 has 48 divisors (see below), whose sum is σ = 3960743345160. Its totient is φ = 828385781760.
The previous prime is 2100120000029. The next prime is 2100120000089. The reversal of 2100120000050 is 500000210012.
It can be written as a sum of positive squares in 12 ways, for example, as 345658157329 + 1754461842721 = 587927^2 + 1324561^2 .
It is a super-2 number, since 2×21001200000502 (a number of 25 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 2100119999986 and 2100120000040.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 561836 + ... + 2125064.
Almost surely, 22100120000050 is an apocalyptic number.
2100120000050 is a deficient number, since it is larger than the sum of its proper divisors (1860623345110).
2100120000050 is a wasteful number, since it uses less digits than its factorization.
2100120000050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1563615 (or 1563610 counting only the distinct ones).
The product of its (nonzero) digits is 20, while the sum is 11.
Adding to 2100120000050 its reverse (500000210012), we get a palindrome (2600120210062).
The spelling of 2100120000050 in words is "two trillion, one hundred billion, one hundred twenty million, fifty", and thus it is an aban number.
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