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210012013 is a prime number
BaseRepresentation
bin11001000010010…
…00011101101101
3112122011201022201
430201020131231
5412230341023
632501141501
75130033631
oct1441103555
9478151281
10210012013
11a8601152
125a3ba891
1334681483
141dc6adc1
1513685bad
hexc84876d

210012013 has 2 divisors, whose sum is σ = 210012014. Its totient is φ = 210012012.

The previous prime is 210011981. The next prime is 210012029. The reversal of 210012013 is 310210012.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 116251524 + 93760489 = 10782^2 + 9683^2 .

It is a cyclic number.

It is not a de Polignac number, because 210012013 - 25 = 210011981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (210012083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105006006 + 105006007.

It is an arithmetic number, because the mean of its divisors is an integer number (105006007).

Almost surely, 2210012013 is an apocalyptic number.

It is an amenable number.

210012013 is a deficient number, since it is larger than the sum of its proper divisors (1).

210012013 is an equidigital number, since it uses as much as digits as its factorization.

210012013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 10.

The square root of 210012013 is about 14491.7912281402. The cubic root of 210012013 is about 594.4035290815.

Adding to 210012013 its reverse (310210012), we get a palindrome (520222025).

The spelling of 210012013 in words is "two hundred ten million, twelve thousand, thirteen".