21001211313 has 4 divisors (see below), whose sum is σ = 28001615088. Its totient is φ = 14000807540.

The previous prime is 21001211311. The next prime is 21001211351. The reversal of 21001211313 is 31311210012.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21001211313 - 2¹ = 21001211311 is a prime.

It is a super-2 number, since 2×21001211313² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21001211292 and 21001211301.

It is not an unprimeable number, because it can be changed into a prime (21001211311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3500201883 + ... + 3500201888.

It is an arithmetic number, because the mean of its divisors is an integer number (7000403772).

Almost surely, 2^21001211313 is an apocalyptic number.

It is an amenable number.

21001211313 is a deficient number, since it is larger than the sum of its proper divisors (7000403775).

21001211313 is an equidigital number, since it uses as much as digits as its factorization.

21001211313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7000403774.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 21001211313 its reverse (31311210012), we get a palindrome (52312421325).

The spelling of 21001211313 in words is "twenty-one billion, one million, two hundred eleven thousand, three hundred thirteen".