210012132000113 has 2 divisors, whose sum is σ = 210012132000114. Its totient is φ = 210012132000112.

The previous prime is 210012132000091. The next prime is 210012132000131. The reversal of 210012132000113 is 311000231210012.

Together with next prime (210012132000131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 154772335207009 + 55239796793104 = 12440753^2 + 7432348^2 .

It is a cyclic number.

It is not a de Polignac number, because 210012132000113 - 2¹⁴ = 210012131983729 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 210012132000091 and 210012132000100.

It is not a weakly prime, because it can be changed into another prime (210012132000413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105006066000056 + 105006066000057.

It is an arithmetic number, because the mean of its divisors is an integer number (105006066000057).

Almost surely, 2^{210012132000113} is an apocalyptic number.

It is an amenable number.

210012132000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

210012132000113 is an equidigital number, since it uses as much as digits as its factorization.

210012132000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 210012132000113 its reverse (311000231210012), we get a palindrome (521012363210125).

The spelling of 210012132000113 in words is "two hundred ten trillion, twelve billion, one hundred thirty-two million, one hundred thirteen", and thus it is an aban number.