210013142404033 has 4 divisors (see below), whose sum is σ = 210013980385108. Its totient is φ = 210012304422960.

The previous prime is 210013142404001. The next prime is 210013142404069. The reversal of 210013142404033 is 330404241310012.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 108761892636609 + 101251249767424 = 10428897^2 + 10062368^2 .

It is a cyclic number.

It is not a de Polignac number, because 210013142404033 - 2⁵ = 210013142404001 is a prime.

It is a super-2 number, since 2×210013142404033² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 210013142403992 and 210013142404010.

It is not an unprimeable number, because it can be changed into a prime (210013142704033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 418614498 + ... + 419115883.

It is an arithmetic number, because the mean of its divisors is an integer number (52503495096277).

Almost surely, 2^{210013142404033} is an apocalyptic number.

It is an amenable number.

210013142404033 is a deficient number, since it is larger than the sum of its proper divisors (837981075).

210013142404033 is an equidigital number, since it uses as much as digits as its factorization.

210013142404033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 837981074.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 210013142404033 its reverse (330404241310012), we get a palindrome (540417383714045).

The spelling of 210013142404033 in words is "two hundred ten trillion, thirteen billion, one hundred forty-two million, four hundred four thousand, thirty-three".