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210020121132011 = 646932465623919
BaseRepresentation
bin101111110000001100011110…
…101101110011101111101011
31000112121201122100022201112022
4233300030132231303233223
5210011432202002211021
62022401524532135055
762144311246533431
oct5760143655635753
91015551570281468
10210020121132011
1160a12040190693
121b67b38176748b
139025a73c24278
1439c105716ad51
15194318a6c91ab
hexbf031eb73beb

210020121132011 has 4 divisors (see below), whose sum is σ = 210052586762400. Its totient is φ = 209987655501624.

The previous prime is 210020121131941. The next prime is 210020121132047. The reversal of 210020121132011 is 110231121020012.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 210020121132011 - 222 = 210020116937707 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (210020121138011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16232805491 + ... + 16232818428.

It is an arithmetic number, because the mean of its divisors is an integer number (52513146690600).

Almost surely, 2210020121132011 is an apocalyptic number.

210020121132011 is a deficient number, since it is larger than the sum of its proper divisors (32465630389).

210020121132011 is an equidigital number, since it uses as much as digits as its factorization.

210020121132011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32465630388.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 210020121132011 its reverse (110231121020012), we get a palindrome (320251242152023).

The spelling of 210020121132011 in words is "two hundred ten trillion, twenty billion, one hundred twenty-one million, one hundred thirty-two thousand, eleven".

Divisors: 1 6469 32465623919 210020121132011