2100251300101 has 4 divisors (see below), whose sum is σ = 2100274432704. Its totient is φ = 2100228167500.

The previous prime is 2100251300099. The next prime is 2100251300111. The reversal of 2100251300101 is 1010031520012.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2100251300101 - 2¹ = 2100251300099 is a prime.

It is a super-2 number, since 2×2100251300101² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2100251300111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11429575 + ... + 11611876.

It is an arithmetic number, because the mean of its divisors is an integer number (525068608176).

Almost surely, 2^{2100251300101} is an apocalyptic number.

It is an amenable number.

2100251300101 is a deficient number, since it is larger than the sum of its proper divisors (23132603).

2100251300101 is an equidigital number, since it uses as much as digits as its factorization.

2100251300101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23132602.

The product of its (nonzero) digits is 60, while the sum is 16.

Adding to 2100251300101 its reverse (1010031520012), we get a palindrome (3110282820113).

The spelling of 2100251300101 in words is "two trillion, one hundred billion, two hundred fifty-one million, three hundred thousand, one hundred one".