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210040123141 = 239132179267
BaseRepresentation
bin1100001110011101011…
…1011110111100000101
3202002011001112210020001
43003213113132330011
511420130232420031
6240254024441301
721113663406022
oct3034727367405
9662131483201
10210040123141
11810941a0332
123485a019231
1316a64417244
14a2476ca549
1556e4b0a861
hex30e75def05

210040123141 has 4 divisors (see below), whose sum is σ = 219172302432. Its totient is φ = 200907943852.

The previous prime is 210040123129. The next prime is 210040123147. The reversal of 210040123141 is 141321040012.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 210040123141 - 217 = 210039992069 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (210040123147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4566089611 + ... + 4566089656.

It is an arithmetic number, because the mean of its divisors is an integer number (54793075608).

Almost surely, 2210040123141 is an apocalyptic number.

It is an amenable number.

210040123141 is a deficient number, since it is larger than the sum of its proper divisors (9132179291).

210040123141 is an equidigital number, since it uses as much as digits as its factorization.

210040123141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9132179290.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 210040123141 its reverse (141321040012), we get a palindrome (351361163153).

The spelling of 210040123141 in words is "two hundred ten billion, forty million, one hundred twenty-three thousand, one hundred forty-one".

Divisors: 1 23 9132179267 210040123141