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21004053013245 = 352775055127079
BaseRepresentation
bin1001100011010011000110…
…00111100110001011111101
32202100222010120100100002110
410301221203013212023331
510223112300032410440
6112401043450444233
74265331004562031
oct461514307461375
982328116310073
1021004053013245
116768850395855
122432886a33679
13b9489b172a63
1452885ca981c1
1526656c345080
hex131a631e62fd

21004053013245 has 16 divisors (see below), whose sum is σ = 33727807877760. Its totient is φ = 11161720588224.

The previous prime is 21004053013217. The next prime is 21004053013301. The reversal of 21004053013245 is 54231035040012.

It is not a de Polignac number, because 21004053013245 - 217 = 21004052882173 is a prime.

It is a super-3 number, since 3×210040530132453 (a number of 41 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2527559385 + ... + 2527567694.

It is an arithmetic number, because the mean of its divisors is an integer number (2107987992360).

Almost surely, 221004053013245 is an apocalyptic number.

It is an amenable number.

21004053013245 is a deficient number, since it is larger than the sum of its proper divisors (12723754864515).

21004053013245 is a wasteful number, since it uses less digits than its factorization.

21004053013245 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5055127364.

The product of its (nonzero) digits is 14400, while the sum is 30.

Adding to 21004053013245 its reverse (54231035040012), we get a palindrome (75235088053257).

The spelling of 21004053013245 in words is "twenty-one trillion, four billion, fifty-three million, thirteen thousand, two hundred forty-five".

Divisors: 1 3 5 15 277 831 1385 4155 5055127079 15165381237 25275635395 75826906185 1400270200883 4200810602649 7001351004415 21004053013245