Base | Representation |
---|---|
bin | 11110100100100001101… |
… | …100100010111111110101 |
3 | 21102211112122222120102112 |
4 | 132210201230202333311 |
5 | 233404421402133212 |
6 | 4245032435420405 |
7 | 304530614126246 |
oct | 36444154427765 |
9 | 7384478876375 |
10 | 2100804333557 |
11 | 73aa45307666 |
12 | 29b197154705 |
13 | 1231498b3317 |
14 | 73972686ccd |
15 | 399a7b48422 |
hex | 1e921b22ff5 |
2100804333557 has 4 divisors (see below), whose sum is σ = 2100814111200. Its totient is φ = 2100794555916.
The previous prime is 2100804333553. The next prime is 2100804333559. The reversal of 2100804333557 is 7553334080012.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2100804333557 - 22 = 2100804333553 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2100804333553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4559123 + ... + 4998720.
It is an arithmetic number, because the mean of its divisors is an integer number (525203527800).
Almost surely, 22100804333557 is an apocalyptic number.
It is an amenable number.
2100804333557 is a deficient number, since it is larger than the sum of its proper divisors (9777643).
2100804333557 is an equidigital number, since it uses as much as digits as its factorization.
2100804333557 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9777642.
The product of its (nonzero) digits is 302400, while the sum is 41.
The spelling of 2100804333557 in words is "two trillion, one hundred billion, eight hundred four million, three hundred thirty-three thousand, five hundred fifty-seven".
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