Base | Representation |
---|---|
bin | 10011100100011110… |
… | …001111011100011011 |
3 | 2000020102200002202202 |
4 | 103210132033130123 |
5 | 321013312031021 |
6 | 13353033320415 |
7 | 1342502366351 |
oct | 234436173433 |
9 | 60212602682 |
10 | 21013002011 |
11 | 8a03323471 |
12 | 40a526610b |
13 | 1c9b517c01 |
14 | 1034a597d1 |
15 | 82eb69a0b |
hex | 4e478f71b |
21013002011 has 2 divisors, whose sum is σ = 21013002012. Its totient is φ = 21013002010.
The previous prime is 21013001951. The next prime is 21013002013. The reversal of 21013002011 is 11020031012.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21013002011 - 214 = 21012985627 is a prime.
Together with 21013002013, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 21013001983 and 21013002001.
It is not a weakly prime, because it can be changed into another prime (21013002013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10506501005 + 10506501006.
It is an arithmetic number, because the mean of its divisors is an integer number (10506501006).
Almost surely, 221013002011 is an apocalyptic number.
21013002011 is a deficient number, since it is larger than the sum of its proper divisors (1).
21013002011 is an equidigital number, since it uses as much as digits as its factorization.
21013002011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 21013002011 its reverse (11020031012), we get a palindrome (32033033023).
The spelling of 21013002011 in words is "twenty-one billion, thirteen million, two thousand, eleven".
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