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2101301011111 is a prime number
BaseRepresentation
bin11110100100111111010…
…011001110001010100111
321102212211021120101221111
4132210333103032022213
5233411431024323421
64245154021125451
7304546124614621
oct36447723161247
97385737511844
102101301011111
1174017a704885
1229b2b5559887
131231c8774073
14739bc615c11
15399d6556ee1
hex1e93f4ce2a7

2101301011111 has 2 divisors, whose sum is σ = 2101301011112. Its totient is φ = 2101301011110.

The previous prime is 2101301011091. The next prime is 2101301011123. The reversal of 2101301011111 is 1111101031012.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2101301011111 - 217 = 2101300880039 is a prime.

It is a super-2 number, since 2×21013010111112 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2101301011091 and 2101301011100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2101301011171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050650505555 + 1050650505556.

It is an arithmetic number, because the mean of its divisors is an integer number (1050650505556).

Almost surely, 22101301011111 is an apocalyptic number.

2101301011111 is a deficient number, since it is larger than the sum of its proper divisors (1).

2101301011111 is an equidigital number, since it uses as much as digits as its factorization.

2101301011111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 2101301011111 its reverse (1111101031012), we get a palindrome (3212402042123).

The spelling of 2101301011111 in words is "two trillion, one hundred one billion, three hundred one million, eleven thousand, one hundred eleven".