Base | Representation |
---|---|
bin | 11110100100111111010… |
… | …011001110001010100111 |
3 | 21102212211021120101221111 |
4 | 132210333103032022213 |
5 | 233411431024323421 |
6 | 4245154021125451 |
7 | 304546124614621 |
oct | 36447723161247 |
9 | 7385737511844 |
10 | 2101301011111 |
11 | 74017a704885 |
12 | 29b2b5559887 |
13 | 1231c8774073 |
14 | 739bc615c11 |
15 | 399d6556ee1 |
hex | 1e93f4ce2a7 |
2101301011111 has 2 divisors, whose sum is σ = 2101301011112. Its totient is φ = 2101301011110.
The previous prime is 2101301011091. The next prime is 2101301011123. The reversal of 2101301011111 is 1111101031012.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2101301011111 - 217 = 2101300880039 is a prime.
It is a super-2 number, since 2×21013010111112 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2101301011091 and 2101301011100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2101301011171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050650505555 + 1050650505556.
It is an arithmetic number, because the mean of its divisors is an integer number (1050650505556).
Almost surely, 22101301011111 is an apocalyptic number.
2101301011111 is a deficient number, since it is larger than the sum of its proper divisors (1).
2101301011111 is an equidigital number, since it uses as much as digits as its factorization.
2101301011111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 13.
Adding to 2101301011111 its reverse (1111101031012), we get a palindrome (3212402042123).
The spelling of 2101301011111 in words is "two trillion, one hundred one billion, three hundred one million, eleven thousand, one hundred eleven".
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