Base | Representation |
---|---|
bin | 10011100101101010… |
… | …111100101000010001 |
3 | 2000021211111200210022 |
4 | 103211222330220101 |
5 | 321033434010113 |
6 | 13355032313225 |
7 | 1343135325335 |
oct | 234552745021 |
9 | 60254450708 |
10 | 21033110033 |
11 | 8a13707971 |
12 | 40abb42815 |
13 | 1ca2738550 |
14 | 10375b17c5 |
15 | 8317dc908 |
hex | 4e5abca11 |
21033110033 has 4 divisors (see below), whose sum is σ = 22651041588. Its totient is φ = 19415178480.
The previous prime is 21033110027. The next prime is 21033110057. The reversal of 21033110033 is 33001133012.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 13138432129 + 7894677904 = 114623^2 + 88852^2 .
It is a cyclic number.
It is not a de Polignac number, because 21033110033 - 216 = 21033044497 is a prime.
It is a super-2 number, since 2×210331100332 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 21033109993 and 21033110020.
It is not an unprimeable number, because it can be changed into a prime (21033110023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 808965758 + ... + 808965783.
It is an arithmetic number, because the mean of its divisors is an integer number (5662760397).
Almost surely, 221033110033 is an apocalyptic number.
It is an amenable number.
21033110033 is a deficient number, since it is larger than the sum of its proper divisors (1617931555).
21033110033 is a wasteful number, since it uses less digits than its factorization.
21033110033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1617931554.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 21033110033 its reverse (33001133012), we get a palindrome (54034243045).
It can be divided in two parts, 2103 and 3110033, that added together give a cube (3112136 = 1463).
The spelling of 21033110033 in words is "twenty-one billion, thirty-three million, one hundred ten thousand, thirty-three".
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