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21041212505053 = 1310871489010863
BaseRepresentation
bin1001100100011000010011…
…11111110011101111011101
32202111112001021111002212211
410302030021333303233131
510224214400400130203
6112430111035400421
74301114601211606
oct462141177635735
982445037432784
1021041212505053
116782589a08a64
122439b175b3111
13b982408b4130
1452a585cd8dad
152674e478ec6d
hex132309ff3bdd

21041212505053 has 8 divisors (see below), whose sum is σ = 22680613480448. Its totient is φ = 19404789553584.

The previous prime is 21041212505011. The next prime is 21041212505057. The reversal of 21041212505053 is 35050521214012.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 21041212505053 - 213 = 21041212496861 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21041212505057) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 744491301 + ... + 744519562.

It is an arithmetic number, because the mean of its divisors is an integer number (2835076685056).

Almost surely, 221041212505053 is an apocalyptic number.

It is an amenable number.

21041212505053 is a deficient number, since it is larger than the sum of its proper divisors (1639400975395).

21041212505053 is a wasteful number, since it uses less digits than its factorization.

21041212505053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1489011963.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 21041212505053 its reverse (35050521214012), we get a palindrome (56091733719065).

The spelling of 21041212505053 in words is "twenty-one trillion, forty-one billion, two hundred twelve million, five hundred five thousand, fifty-three".

Divisors: 1 13 1087 14131 1489010863 19357141219 1618554808081 21041212505053