211000313 has 2 divisors, whose sum is σ = 211000314. Its totient is φ = 211000312.

The previous prime is 211000247. The next prime is 211000331. The reversal of 211000313 is 313000112.

Together with next prime (211000331) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 177209344 + 33790969 = 13312^2 + 5813^2 .

It is a cyclic number.

It is not a de Polignac number, because 211000313 - 2¹⁰ = 210999289 is a prime.

It is a super-2 number, since 2×211000313² = 89042264172195938, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 211000294 and 211000303.

It is not a weakly prime, because it can be changed into another prime (211000333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105500156 + 105500157.

It is an arithmetic number, because the mean of its divisors is an integer number (105500157).

Almost surely, 2^211000313 is an apocalyptic number.

It is an amenable number.

211000313 is a deficient number, since it is larger than the sum of its proper divisors (1).

211000313 is an equidigital number, since it uses as much as digits as its factorization.

211000313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 11.

The square root of 211000313 is about 14525.8498202343. The cubic root of 211000313 is about 595.3344756891.

Adding to 211000313 its reverse (313000112), we get a palindrome (524000425).

The spelling of 211000313 in words is "two hundred eleven million, three hundred thirteen", and thus it is an aban number.