211001000100113 has 4 divisors (see below), whose sum is σ = 211605587493300. Its totient is φ = 210396412706928.

The previous prime is 211001000100089. The next prime is 211001000100119. The reversal of 211001000100113 is 311001000100112.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 127871610329089 + 83129389771024 = 11308033^2 + 9117532^2 .

It is a cyclic number.

It is not a de Polignac number, because 211001000100113 - 2²⁰ = 211000999051537 is a prime.

It is a super-2 number, since 2×211001000100113² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211001000100094 and 211001000100103.

It is not an unprimeable number, because it can be changed into a prime (211001000100119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 302293696070 + ... + 302293696767.

It is an arithmetic number, because the mean of its divisors is an integer number (52901396873325).

Almost surely, 2^{211001000100113} is an apocalyptic number.

It is an amenable number.

211001000100113 is a deficient number, since it is larger than the sum of its proper divisors (604587393187).

211001000100113 is an equidigital number, since it uses as much as digits as its factorization.

211001000100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 604587393186.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 211001000100113 its reverse (311001000100112), we get a palindrome (522002000200225).

Subtracting 211001000100113 from its reverse (311001000100112), we obtain a palindrome (99999999999999).

The spelling of 211001000100113 in words is "two hundred eleven trillion, one billion, one hundred thousand, one hundred thirteen".