Base | Representation |
---|---|
bin | 11110101101000110011… |
… | …001110011000010110101 |
3 | 21110201022020021110211112 |
4 | 132231012121303002311 |
5 | 234032300042011013 |
6 | 4253154131244405 |
7 | 305305006004102 |
oct | 36550631630265 |
9 | 7421266243745 |
10 | 2110010110133 |
11 | 743939776882 |
12 | 2a0b26149705 |
13 | 123c85b90cb3 |
14 | 741a7145aa9 |
15 | 39d45e20ba8 |
hex | 1eb466730b5 |
2110010110133 has 2 divisors, whose sum is σ = 2110010110134. Its totient is φ = 2110010110132.
The previous prime is 2110010110081. The next prime is 2110010110177. The reversal of 2110010110133 is 3310110100112.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1714572879889 + 395437230244 = 1309417^2 + 628838^2 .
It is a cyclic number.
It is not a de Polignac number, because 2110010110133 - 212 = 2110010106037 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2110010110333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055005055066 + 1055005055067.
It is an arithmetic number, because the mean of its divisors is an integer number (1055005055067).
Almost surely, 22110010110133 is an apocalyptic number.
It is an amenable number.
2110010110133 is a deficient number, since it is larger than the sum of its proper divisors (1).
2110010110133 is an equidigital number, since it uses as much as digits as its factorization.
2110010110133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 2110010110133 its reverse (3310110100112), we get a palindrome (5420120210245).
The spelling of 2110010110133 in words is "two trillion, one hundred ten billion, ten million, one hundred ten thousand, one hundred thirty-three".
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