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211002022117 is a prime number
BaseRepresentation
bin1100010010000010110…
…0110101100011100101
3202011122002112022120001
43010200230311203211
511424113004201432
6240533305341301
721146553411145
oct3044054654345
9664562468501
10211002022117
1181538160267
1234a88197831
1316b887a4033
14a2d935a925
15574e2b29e7
hex3120b358e5

211002022117 has 2 divisors, whose sum is σ = 211002022118. Its totient is φ = 211002022116.

The previous prime is 211002022097. The next prime is 211002022151. The reversal of 211002022117 is 711220200112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 112572999361 + 98429022756 = 335519^2 + 313734^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211002022117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211002022094 and 211002022103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211002022717) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105501011058 + 105501011059.

It is an arithmetic number, because the mean of its divisors is an integer number (105501011059).

Almost surely, 2211002022117 is an apocalyptic number.

It is an amenable number.

211002022117 is a deficient number, since it is larger than the sum of its proper divisors (1).

211002022117 is an equidigital number, since it uses as much as digits as its factorization.

211002022117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 112, while the sum is 19.

Adding to 211002022117 its reverse (711220200112), we get a palindrome (922222222229).

The spelling of 211002022117 in words is "two hundred eleven billion, two million, twenty-two thousand, one hundred seventeen".