Base | Representation |
---|---|
bin | 101111111110100111010011… |
… | …110000100100110000001011 |
3 | 1000200010110021110122000020111 |
4 | 233332213103300210300023 |
5 | 210124201012224324321 |
6 | 2024441040550535151 |
7 | 62306020212535132 |
oct | 5776472360446013 |
9 | 1020113243560214 |
10 | 211011001011211 |
11 | 61264299030865 |
12 | 1b7bb4193674b7 |
13 | 90983378a290b |
14 | 3a16db6250919 |
15 | 195dd314375e1 |
hex | bfe9d3c24c0b |
211011001011211 has 2 divisors, whose sum is σ = 211011001011212. Its totient is φ = 211011001011210.
The previous prime is 211011001011203. The next prime is 211011001011233. The reversal of 211011001011211 is 112110100110112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211011001011211 - 23 = 211011001011203 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 211011001011191 and 211011001011200.
It is not a weakly prime, because it can be changed into another prime (211011001011241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105505500505605 + 105505500505606.
It is an arithmetic number, because the mean of its divisors is an integer number (105505500505606).
Almost surely, 2211011001011211 is an apocalyptic number.
211011001011211 is a deficient number, since it is larger than the sum of its proper divisors (1).
211011001011211 is an equidigital number, since it uses as much as digits as its factorization.
211011001011211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 13.
Adding to 211011001011211 its reverse (112110100110112), we get a palindrome (323121101121323).
The spelling of 211011001011211 in words is "two hundred eleven trillion, eleven billion, one million, eleven thousand, two hundred eleven".
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