211011131131333 has 8 divisors (see below), whose sum is σ = 227297474396888. Its totient is φ = 194732604693504.

The previous prime is 211011131131319. The next prime is 211011131131363. The reversal of 211011131131333 is 333131131110112.

It can be written as a sum of positive squares in 4 ways, for example, as 16245541764 + 210994885589569 = 127458^2 + 14525663^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 211011131131333 - 2³⁷ = 210873692177861 is a prime.

It is a super-2 number, since 2×211011131131333² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211011131131298 and 211011131131307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211011131131313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1954150860 + ... + 1954258837.

It is an arithmetic number, because the mean of its divisors is an integer number (28412184299611).

Almost surely, 2^{211011131131333} is an apocalyptic number.

It is an amenable number.

211011131131333 is a deficient number, since it is larger than the sum of its proper divisors (16286343265555).

211011131131333 is a wasteful number, since it uses less digits than its factorization.

211011131131333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3908413863.

The product of its (nonzero) digits is 486, while the sum is 25.

Adding to 211011131131333 its reverse (333131131110112), we get a palindrome (544142262241445).

The spelling of 211011131131333 in words is "two hundred eleven trillion, eleven billion, one hundred thirty-one million, one hundred thirty-one thousand, three hundred thirty-three".