Base | Representation |
---|---|
bin | 1100010010000100111… |
… | …1111011001010101011 |
3 | 202011122201211121212112 |
4 | 3010201033323022223 |
5 | 11424122333021024 |
6 | 240534234432535 |
7 | 21150024530426 |
oct | 3044117731253 |
9 | 664581747775 |
10 | 211011220139 |
11 | 81542372935 |
12 | 34a8b29274b |
13 | 16b8a674855 |
14 | a2da6729bd |
15 | 574eecd00e |
hex | 31213fb2ab |
211011220139 has 2 divisors, whose sum is σ = 211011220140. Its totient is φ = 211011220138.
The previous prime is 211011220097. The next prime is 211011220141. The reversal of 211011220139 is 931022110112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211011220139 is a prime.
Together with 211011220141, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (211011220339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105505610069 + 105505610070.
It is an arithmetic number, because the mean of its divisors is an integer number (105505610070).
Almost surely, 2211011220139 is an apocalyptic number.
211011220139 is a deficient number, since it is larger than the sum of its proper divisors (1).
211011220139 is an equidigital number, since it uses as much as digits as its factorization.
211011220139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 23.
The spelling of 211011220139 in words is "two hundred eleven billion, eleven million, two hundred twenty thousand, one hundred thirty-nine".
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