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211011220139 is a prime number
BaseRepresentation
bin1100010010000100111…
…1111011001010101011
3202011122201211121212112
43010201033323022223
511424122333021024
6240534234432535
721150024530426
oct3044117731253
9664581747775
10211011220139
1181542372935
1234a8b29274b
1316b8a674855
14a2da6729bd
15574eecd00e
hex31213fb2ab

211011220139 has 2 divisors, whose sum is σ = 211011220140. Its totient is φ = 211011220138.

The previous prime is 211011220097. The next prime is 211011220141. The reversal of 211011220139 is 931022110112.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211011220139 is a prime.

Together with 211011220141, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (211011220339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105505610069 + 105505610070.

It is an arithmetic number, because the mean of its divisors is an integer number (105505610070).

Almost surely, 2211011220139 is an apocalyptic number.

211011220139 is a deficient number, since it is larger than the sum of its proper divisors (1).

211011220139 is an equidigital number, since it uses as much as digits as its factorization.

211011220139 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 23.

The spelling of 211011220139 in words is "two hundred eleven billion, eleven million, two hundred twenty thousand, one hundred thirty-nine".