Base | Representation |
---|---|
bin | 11110101101001100111… |
… | …101011000000100100011 |
3 | 21110201120220020112202011 |
4 | 132231030331120010203 |
5 | 234033011221201011 |
6 | 4253213100533351 |
7 | 305310512624461 |
oct | 36551475300443 |
9 | 7421526215664 |
10 | 2110120100131 |
11 | 7439958709aa |
12 | 2a0b56b51257 |
13 | 123ca28c1934 |
14 | 741b79b7831 |
15 | 39d508ea621 |
hex | 1eb4cf58123 |
2110120100131 has 2 divisors, whose sum is σ = 2110120100132. Its totient is φ = 2110120100130.
The previous prime is 2110120100111. The next prime is 2110120100159. The reversal of 2110120100131 is 1310010210112.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2110120100131 - 27 = 2110120100003 is a prime.
It is a super-2 number, since 2×21101201001312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2110120100111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055060050065 + 1055060050066.
It is an arithmetic number, because the mean of its divisors is an integer number (1055060050066).
Almost surely, 22110120100131 is an apocalyptic number.
2110120100131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2110120100131 is an equidigital number, since it uses as much as digits as its factorization.
2110120100131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 2110120100131 its reverse (1310010210112), we get a palindrome (3420130310243).
The spelling of 2110120100131 in words is "two trillion, one hundred ten billion, one hundred twenty million, one hundred thousand, one hundred thirty-one".
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