Base | Representation |
---|---|
bin | 1001100110001000000011… |
… | …00110100100001001110011 |
3 | 2202201020212222211011111112 |
4 | 10303010001212210021303 |
5 | 10231210230002241034 |
6 | 112513431421503535 |
7 | 4305340302623165 |
oct | 463040146441163 |
9 | 82636788734445 |
10 | 21101201212019 |
11 | 67a5a72a82435 |
12 | 2449679711bab |
13 | ba0ab0bb9046 |
14 | 52d43708c935 |
15 | 268d560117ce |
hex | 1331019a4273 |
21101201212019 has 2 divisors, whose sum is σ = 21101201212020. Its totient is φ = 21101201212018.
The previous prime is 21101201212009. The next prime is 21101201212027. The reversal of 21101201212019 is 91021210210112.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21101201212019 - 228 = 21100932776563 is a prime.
It is a super-2 number, since 2×211012012120192 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21101201211985 and 21101201212003.
It is not a weakly prime, because it can be changed into another prime (21101201212009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10550600606009 + 10550600606010.
It is an arithmetic number, because the mean of its divisors is an integer number (10550600606010).
Almost surely, 221101201212019 is an apocalyptic number.
21101201212019 is a deficient number, since it is larger than the sum of its proper divisors (1).
21101201212019 is an equidigital number, since it uses as much as digits as its factorization.
21101201212019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 23.
The spelling of 21101201212019 in words is "twenty-one trillion, one hundred one billion, two hundred one million, two hundred twelve thousand, nineteen".
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