Base | Representation |
---|---|
bin | 11110101101001101101… |
… | …010110001100101110101 |
3 | 21110201121201122011212022 |
4 | 132231031222301211311 |
5 | 234033022243014031 |
6 | 4253214204002525 |
7 | 305311016032343 |
oct | 36551552614565 |
9 | 7421551564768 |
10 | 2110132001141 |
11 | 7439a155a34a |
12 | 2a0b5ab30445 |
13 | 123ca51ca858 |
14 | 741b93d4993 |
15 | 39d5199b97b |
hex | 1eb4dab1975 |
2110132001141 has 2 divisors, whose sum is σ = 2110132001142. Its totient is φ = 2110132001140.
The previous prime is 2110132001123. The next prime is 2110132001177. The reversal of 2110132001141 is 1411002310112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2096313058225 + 13818942916 = 1447865^2 + 117554^2 .
It is a cyclic number.
It is not a de Polignac number, because 2110132001141 - 214 = 2110131984757 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2110132001641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055066000570 + 1055066000571.
It is an arithmetic number, because the mean of its divisors is an integer number (1055066000571).
Almost surely, 22110132001141 is an apocalyptic number.
It is an amenable number.
2110132001141 is a deficient number, since it is larger than the sum of its proper divisors (1).
2110132001141 is an equidigital number, since it uses as much as digits as its factorization.
2110132001141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 2110132001141 its reverse (1411002310112), we get a palindrome (3521134311253).
The spelling of 2110132001141 in words is "two trillion, one hundred ten billion, one hundred thirty-two million, one thousand, one hundred forty-one".
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