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211013517855911 is a prime number
BaseRepresentation
bin101111111110101001101001…
…110001100100110010100111
31000200010200202212111222002212
4233332221221301210302213
5210124221141032342121
62024442134415354035
762306136453421601
oct5776515161446247
91020120685458085
10211013517855911
116126536a79a501
121b7bba0022291b
13909864914c234
143a17174608171
15195de2c38e25b
hexbfea69c64ca7

211013517855911 has 2 divisors, whose sum is σ = 211013517855912. Its totient is φ = 211013517855910.

The previous prime is 211013517855851. The next prime is 211013517855913. The reversal of 211013517855911 is 119558715310112.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211013517855911 is a prime.

Together with 211013517855913, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 211013517855911.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211013517855913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105506758927955 + 105506758927956.

It is an arithmetic number, because the mean of its divisors is an integer number (105506758927956).

Almost surely, 2211013517855911 is an apocalyptic number.

211013517855911 is a deficient number, since it is larger than the sum of its proper divisors (1).

211013517855911 is an equidigital number, since it uses as much as digits as its factorization.

211013517855911 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 378000, while the sum is 50.

The spelling of 211013517855911 in words is "two hundred eleven trillion, thirteen billion, five hundred seventeen million, eight hundred fifty-five thousand, nine hundred eleven".