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211021300231 = 730145900033
BaseRepresentation
bin1100010010000111011…
…0011000001000000111
3202011200102210202011021
43010201312120020013
511424132423101411
6240535234452011
721150206312440
oct3044166301007
9664612722137
10211021300231
1181548028195
1234a92734007
1316b8c7939c1
14a2dbb382c7
155750d1ea71
hex3121d98207

211021300231 has 4 divisors (see below), whose sum is σ = 241167200272. Its totient is φ = 180875400192.

The previous prime is 211021300229. The next prime is 211021300241. The reversal of 211021300231 is 132003120112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 211021300231 - 21 = 211021300229 is a prime.

It is a super-2 number, since 2×2110213002312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211021300241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15072950010 + ... + 15072950023.

It is an arithmetic number, because the mean of its divisors is an integer number (60291800068).

Almost surely, 2211021300231 is an apocalyptic number.

211021300231 is a deficient number, since it is larger than the sum of its proper divisors (30145900041).

211021300231 is an equidigital number, since it uses as much as digits as its factorization.

211021300231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30145900040.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 211021300231 its reverse (132003120112), we get a palindrome (343024420343).

The spelling of 211021300231 in words is "two hundred eleven billion, twenty-one million, three hundred thousand, two hundred thirty-one".

Divisors: 1 7 30145900033 211021300231