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211041141341 = 619340938839
BaseRepresentation
bin1100010010001100001…
…0000100001001011101
3202011201211010210001012
43010203002010021131
511424203013010331
6240541224025005
721150540050312
oct3044302041135
9664654123035
10211041141341
118155824a0a8
1234a99302165
1316b9391c9c4
14a300620d09
15575293d82b
hex312308425d

211041141341 has 4 divisors (see below), whose sum is σ = 211382080800. Its totient is φ = 210700201884.

The previous prime is 211041141307. The next prime is 211041141391. The reversal of 211041141341 is 143141140112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211041141341 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211041141391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 170468801 + ... + 170470038.

It is an arithmetic number, because the mean of its divisors is an integer number (52845520200).

Almost surely, 2211041141341 is an apocalyptic number.

It is an amenable number.

211041141341 is a deficient number, since it is larger than the sum of its proper divisors (340939459).

211041141341 is an equidigital number, since it uses as much as digits as its factorization.

211041141341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 340939458.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 211041141341 its reverse (143141140112), we get a palindrome (354182281453).

The spelling of 211041141341 in words is "two hundred eleven billion, forty-one million, one hundred forty-one thousand, three hundred forty-one".

Divisors: 1 619 340938839 211041141341