Base | Representation |
---|---|
bin | 1100010010001100100… |
… | …1101000010010110111 |
3 | 202011201221212112022002 |
4 | 3010203021220102313 |
5 | 11424204014440112 |
6 | 240541334325515 |
7 | 21150562646663 |
oct | 3044311502267 |
9 | 664657775262 |
10 | 211043124407 |
11 | 81559383aa5 |
12 | 34a99ab989b |
13 | 16b9416550b |
14 | a3009b98a3 |
15 | 5752bd11c2 |
hex | 31232684b7 |
211043124407 has 2 divisors, whose sum is σ = 211043124408. Its totient is φ = 211043124406.
The previous prime is 211043124389. The next prime is 211043124449. The reversal of 211043124407 is 704421340112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211043124407 - 26 = 211043124343 is a prime.
It is a super-3 number, since 3×2110431244073 (a number of 35 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 211043124407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211043124107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105521562203 + 105521562204.
It is an arithmetic number, because the mean of its divisors is an integer number (105521562204).
Almost surely, 2211043124407 is an apocalyptic number.
211043124407 is a deficient number, since it is larger than the sum of its proper divisors (1).
211043124407 is an equidigital number, since it uses as much as digits as its factorization.
211043124407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5376, while the sum is 29.
Adding to 211043124407 its reverse (704421340112), we get a palindrome (915464464519).
The spelling of 211043124407 in words is "two hundred eleven billion, forty-three million, one hundred twenty-four thousand, four hundred seven".
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