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21110010133 = 73503574907
BaseRepresentation
bin10011101010010000…
…010011000100010101
32000111012012121220011
4103222100103010111
5321213130311013
613410420440221
71345061061022
oct235220230425
960435177804
1021110010133
118a53061073
124111849071
131cb5651974
1410438ac549
1583842cc3d
hex4ea413115

21110010133 has 8 divisors (see below), whose sum is σ = 21441768768. Its totient is φ = 20779402464.

The previous prime is 21110010109. The next prime is 21110010143. The reversal of 21110010133 is 33101001112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21110010133 is a prime.

It is a super-3 number, since 3×211100101333 (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21110010143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 250735 + ... + 324172.

It is an arithmetic number, because the mean of its divisors is an integer number (2680221096).

Almost surely, 221110010133 is an apocalyptic number.

It is an amenable number.

21110010133 is a deficient number, since it is larger than the sum of its proper divisors (331758635).

21110010133 is an equidigital number, since it uses as much as digits as its factorization.

21110010133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 575483.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 21110010133 its reverse (33101001112), we get a palindrome (54211011245).

The spelling of 21110010133 in words is "twenty-one billion, one hundred ten million, ten thousand, one hundred thirty-three".

Divisors: 1 73 503 36719 574907 41968211 289178221 21110010133