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2111012112017 is a prime number
BaseRepresentation
bin11110101110000010001…
…000001000011010010001
321110210220001201110000102
4132232002020020122101
5234041323100041032
64253441403502145
7305341563613304
oct36560210103221
97423801643012
102111012112017
11744303337706
122a1165827955
131240b564c413
1474260254b3b
1539da3d9a362
hex1eb82208691

2111012112017 has 2 divisors, whose sum is σ = 2111012112018. Its totient is φ = 2111012112016.

The previous prime is 2111012111981. The next prime is 2111012112019. The reversal of 2111012112017 is 7102112101112.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1794753219856 + 316258892161 = 1339684^2 + 562369^2 .

It is a cyclic number.

It is not a de Polignac number, because 2111012112017 - 218 = 2111011849873 is a prime.

Together with 2111012112019, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2111012112017.

It is not a weakly prime, because it can be changed into another prime (2111012112019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055506056008 + 1055506056009.

It is an arithmetic number, because the mean of its divisors is an integer number (1055506056009).

Almost surely, 22111012112017 is an apocalyptic number.

It is an amenable number.

2111012112017 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111012112017 is an equidigital number, since it uses as much as digits as its factorization.

2111012112017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 20.

Adding to 2111012112017 its reverse (7102112101112), we get a palindrome (9213124213129).

The spelling of 2111012112017 in words is "two trillion, one hundred eleven billion, twelve million, one hundred twelve thousand, seventeen".