Base | Representation |
---|---|
bin | 10011101010010001… |
… | …000011111000001001 |
3 | 2000111012120210010202 |
4 | 103222101003320021 |
5 | 321213203210212 |
6 | 13410425021545 |
7 | 1345062552626 |
oct | 235221037011 |
9 | 60435523122 |
10 | 21110210057 |
11 | 8a531882a2 |
12 | 41119248b5 |
13 | 1cb56c1971 |
14 | 104392134d |
15 | 83846c0c2 |
hex | 4ea443e09 |
21110210057 has 2 divisors, whose sum is σ = 21110210058. Its totient is φ = 21110210056.
The previous prime is 21110210021. The next prime is 21110210059. The reversal of 21110210057 is 75001201112.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 21053719801 + 56490256 = 145099^2 + 7516^2 .
It is a cyclic number.
It is not a de Polignac number, because 21110210057 - 210 = 21110209033 is a prime.
Together with 21110210059, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (21110210059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10555105028 + 10555105029.
It is an arithmetic number, because the mean of its divisors is an integer number (10555105029).
Almost surely, 221110210057 is an apocalyptic number.
It is an amenable number.
21110210057 is a deficient number, since it is larger than the sum of its proper divisors (1).
21110210057 is an equidigital number, since it uses as much as digits as its factorization.
21110210057 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 140, while the sum is 20.
Adding to 21110210057 its reverse (75001201112), we get a palindrome (96111411169).
The spelling of 21110210057 in words is "twenty-one billion, one hundred ten million, two hundred ten thousand, fifty-seven".
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