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211102132121 is a prime number
BaseRepresentation
bin1100010010011010101…
…0101110011110011001
3202011220001220102122222
43010212222232132121
511424314121211441
6240551243153425
721152210342066
oct3044652563631
9664801812588
10211102132121
1181589717401
1234ab5815875
1316ba345591a
14a308779c6d
155757e89d4b
hex3126aae799

211102132121 has 2 divisors, whose sum is σ = 211102132122. Its totient is φ = 211102132120.

The previous prime is 211102132099. The next prime is 211102132193. The reversal of 211102132121 is 121231201112.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 134550309721 + 76551822400 = 366811^2 + 276680^2 .

It is a cyclic number.

It is not a de Polignac number, because 211102132121 - 214 = 211102115737 is a prime.

It is a super-2 number, since 2×2111021321212 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 211102132121.

It is not a weakly prime, because it can be changed into another prime (211102132421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105551066060 + 105551066061.

It is an arithmetic number, because the mean of its divisors is an integer number (105551066061).

Almost surely, 2211102132121 is an apocalyptic number.

It is an amenable number.

211102132121 is a deficient number, since it is larger than the sum of its proper divisors (1).

211102132121 is an equidigital number, since it uses as much as digits as its factorization.

211102132121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 211102132121 its reverse (121231201112), we get a palindrome (332333333233).

The spelling of 211102132121 in words is "two hundred eleven billion, one hundred two million, one hundred thirty-two thousand, one hundred twenty-one".