Base | Representation |
---|---|
bin | 1100010010011100100… |
… | …0110100010000010101 |
3 | 202011220121202011221222 |
4 | 3010213020310100111 |
5 | 11424323131120432 |
6 | 240552124220125 |
7 | 21152334364133 |
oct | 3044710642025 |
9 | 664817664858 |
10 | 211110020117 |
11 | 81593114807 |
12 | 34ab839a645 |
13 | 16ba4c88089 |
14 | a309830753 |
15 | 57589e7112 |
hex | 3127234415 |
211110020117 has 2 divisors, whose sum is σ = 211110020118. Its totient is φ = 211110020116.
The previous prime is 211110020081. The next prime is 211110020123. The reversal of 211110020117 is 711020011112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 119025690001 + 92084330116 = 345001^2 + 303454^2 .
It is a cyclic number.
It is not a de Polignac number, because 211110020117 - 210 = 211110019093 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 211110020095 and 211110020104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211110020617) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105555010058 + 105555010059.
It is an arithmetic number, because the mean of its divisors is an integer number (105555010059).
Almost surely, 2211110020117 is an apocalyptic number.
It is an amenable number.
211110020117 is a deficient number, since it is larger than the sum of its proper divisors (1).
211110020117 is an equidigital number, since it uses as much as digits as its factorization.
211110020117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28, while the sum is 17.
Adding to 211110020117 its reverse (711020011112), we get a palindrome (922130031229).
The spelling of 211110020117 in words is "two hundred eleven billion, one hundred ten million, twenty thousand, one hundred seventeen".
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