Search a number
-
+
2111111001211 is a prime number
BaseRepresentation
bin11110101110001000000…
…001010111010001111011
321110211010221210112111011
4132232020001113101323
5234042023404014321
64253455255214351
7305344204301062
oct36561001272173
97424127715434
102111111001211
1174435413a613
122a11929773b7
131240ccc94434
147426d4371d9
1539dac8d0ae1
hex1eb8805747b

2111111001211 has 2 divisors, whose sum is σ = 2111111001212. Its totient is φ = 2111111001210.

The previous prime is 2111111001161. The next prime is 2111111001217. The reversal of 2111111001211 is 1121001111112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2111111001211 - 223 = 2111102612603 is a prime.

It is a super-3 number, since 3×21111110012113 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 2111111001191 and 2111111001200.

It is not a weakly prime, because it can be changed into another prime (2111111001217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055555500605 + 1055555500606.

It is an arithmetic number, because the mean of its divisors is an integer number (1055555500606).

Almost surely, 22111111001211 is an apocalyptic number.

2111111001211 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111111001211 is an equidigital number, since it uses as much as digits as its factorization.

2111111001211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 2111111001211 its reverse (1121001111112), we get a palindrome (3232112112323).

The spelling of 2111111001211 in words is "two trillion, one hundred eleven billion, one hundred eleven million, one thousand, two hundred eleven".