Search a number
-
+
2111131420199 = 20031053984733
BaseRepresentation
bin11110101110001001001…
…111010000011000100111
321110211012101012221001222
4132232021033100120213
5234042044120421244
64253501305010555
7305344542663464
oct36561117203047
97424171187058
102111131420199
1174436471670a
122a1199783a5b
13124104293489
147427203066b
1539dae5b5bee
hex1eb893d0627

2111131420199 has 4 divisors (see below), whose sum is σ = 2112185406936. Its totient is φ = 2110077433464.

The previous prime is 2111131420183. The next prime is 2111131420253. The reversal of 2111131420199 is 9910241311112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2111131420199 - 24 = 2111131420183 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2111131420109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 526990364 + ... + 526994369.

It is an arithmetic number, because the mean of its divisors is an integer number (528046351734).

Almost surely, 22111131420199 is an apocalyptic number.

2111131420199 is a deficient number, since it is larger than the sum of its proper divisors (1053986737).

2111131420199 is a wasteful number, since it uses less digits than its factorization.

2111131420199 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1053986736.

The product of its (nonzero) digits is 3888, while the sum is 35.

The spelling of 2111131420199 in words is "two trillion, one hundred eleven billion, one hundred thirty-one million, four hundred twenty thousand, one hundred ninety-nine".

Divisors: 1 2003 1053984733 2111131420199