Base | Representation |
---|---|
bin | 1001100110011100001010… |
… | …10000101011000001100111 |
3 | 2202202021202120122102212202 |
4 | 10303032011100223001213 |
5 | 10231344334000000403 |
6 | 112522415141205115 |
7 | 4306202020043315 |
oct | 463160520530147 |
9 | 82667676572782 |
10 | 21112000000103 |
11 | 67aa60467a791 |
12 | 244b79210079b |
13 | ba1b1222388c |
14 | 52db7d3430b5 |
15 | 2692890a7688 |
hex | 13338542b067 |
21112000000103 has 2 divisors, whose sum is σ = 21112000000104. Its totient is φ = 21112000000102.
The previous prime is 21112000000097. The next prime is 21112000000123. The reversal of 21112000000103 is 30100000021112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21112000000103 - 222 = 21111995805799 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21112000000123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556000000051 + 10556000000052.
It is an arithmetic number, because the mean of its divisors is an integer number (10556000000052).
Almost surely, 221112000000103 is an apocalyptic number.
21112000000103 is a deficient number, since it is larger than the sum of its proper divisors (1).
21112000000103 is an equidigital number, since it uses as much as digits as its factorization.
21112000000103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 21112000000103 its reverse (30100000021112), we get a palindrome (51212000021215).
The spelling of 21112000000103 in words is "twenty-one trillion, one hundred twelve billion, one hundred three", and thus it is an aban number.
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